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The reactions of Pb(OAc)2 with 1,2,4,5-benzenetetrathiol, 1,4-benzenedithiol, and benzenehexathiol in ethylenediamine yield bright yellow Pb2(S2C6H2S2)(en)n, orange-red Pb3(SC6H4S)3(en)2n, and brown Pb3C6S6n, respectively. The structures of Pb2(S2C6H2S2)(en)n and Pb3C6S6n were solved by synchrotron X-ray powder diffraction, while the structure of Pb3(SC6H4S)3(en)2n was solved by single-crystal X-ray diffraction. The bonding in Pb2(S2C6H2S2)(en)n indicates the presence of "molecular" units, while in Pb3C6S6n, the bonding most resembles that in an inorganic solid such as PbS. The differences in bonding are reflected in the optical and electrical properties of the materials; Pb3C6S6n is a semiconductor.
Turner et al. (Sat,) studied this question.