Abstract Let M be an open (complete and non-compact) manifold with Ric 0 Ric ≥ 0 and escape rate not 1/2. It is known that under these conditions, the fundamental group ₁ (M) π 1 (M) has a finitely generated torsion-free nilpotent subgroup N N of finite index, as long as ₁ (M) π 1 (M) is an infinite group. We show that the nilpotency step of N N must be reflected in the asymptotic geometry of the universal cover M M ~, in terms of the Hausdorff dimension of an isometric R R -orbit: there exist an asymptotic cone (Y, y) of M M ~ and a closed R R -subgroup L of the isometry group of Y such that its orbit Ly has Hausdorff dimension at least the nilpotency step of N N. This resolves a question raised by Wei and the author (see Pan and Wei in Geom Funct Anal 32: 676–685, 2022, Remark 1. 7 and Pan in Geom Topol 28: 1409–1436, 2024, Conjecture 0. 2).
Building similarity graph...
Analyzing shared references across papers
Loading...
Jiayin Pan
University of California, Santa Cruz
Mathematische Annalen
University of California, Santa Cruz
Building similarity graph...
Analyzing shared references across papers
Loading...
Jiayin Pan (Thu,) studied this question.
synapsesocial.com/papers/698828eb0fc35cd7a8848d86 — DOI: https://doi.org/10.1007/s00208-026-03378-9
Synapse has enriched 5 closely related papers on similar clinical questions. Consider them for comparative context: