Abstract We establish a conditional proof that the Riemann Hypothesis follows from the SRNUDT Boundary Theorem plus one precisely-stated open algebraic problem (Conjecture 1). The prime numbers constitute a SRNUDT tiling of the positive integers under the divisibility partial order. The non-trivial zeros of the Riemann zeta function ζ(s) are identified as the remainder class R ∈ H¹(F) of the prime SRNUDT system — the cohomological obstruction to globally synthesizing the prime tiling's organizational structure. The critical line Re(s) = 1/2 is the fixed-point set Fix(σ₃) of a composition of symmetries that characterize the zeros of ζ(s). Assuming Conjecture 1 and invoking the SRNUDT Boundary Theorem (Ploof 2026, Paper A), R localizes to Fix(σ₃), placing all non-trivial zeros on Re(s) = 1/2. The proof does NOT unconditionally establish RH. This paper establishes a CONDITIONAL REDUCTION: RH ← Conjecture 1 ∧ Boundary Theorem ∧ SRNUDT axioms. The reduction is logically valid; the open problem is to prove Conjecture 1 and the Boundary Theorem independently. We provide the precise statement of Conjecture 1, discuss why it is tractable, and explain its connection to the De Bruijn-Newman constant via the Rodgers-Tao theorem.
Bradley Ploof (Mon,) studied this question.