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AbstractFor a natural number n, the permutation (n!) is defined as the left-to-right product of the first n cycles, namely, . In this article, we prove that for any natural number n, 2 is a primitive root of 2n + 1 if and only if 2n + 1 = pk for some odd prime number p and for some natural number k such that the permutation (n!) has exactly k orbits. We also prove that a prime number p is a Sophie Germain prime if and only if the permutation (p!) has at most two orbits.Mathematics Subject Classification (2020): Primary: 20B30Secondary: 11A41Key words: Primitive rootSophie Germain primepermutationorbits of permutation
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Makeshwari et al. (Wed,) studied this question.
synapsesocial.com/papers/68e5e4ecb6db643587579a73 — DOI: https://doi.org/10.2989/16073606.2024.2374787
M. Makeshwari
V. P. Ramesh
Central University of Tamil Nadu
R. Thangadurai
Homi Bhabha National Institute
Quaestiones Mathematicae
Harish-Chandra Research Institute
Homi Bhabha National Institute
Central University of Tamil Nadu
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