The compound Bi₁₀₷Yb₀₇O₃ was obtained by solid-state synthesis. It has a cubic structure, space group Fm3m, lattice parameter a = 0.54202 nm. The dissolution enthalpy of Bi₁₀₷Yb₀₷O₃ was determined by solution calorimetry in 2 M HCl and equals ∆solH⁰ = −227.8 ± 6.3 kJ/mol. On this basis, the standard formation enthalpy of Bi₁₀₷Yb₀₷O₃ was determined: ∆fH⁰ = −996.0 ± 7.9 kJ/mol. The lattice enthalpy for Bi₁₀₷Yb₀₷O₃ was calculated, equaling ∆latH⁰ = −13278 kJ/mol.
N.I. Matskevich (Wed,) studied this question.