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Let T be a quasinilpotent operator on a Banach space. Under assumptions of a certain nonsymmetry in the growth of the resolvent of T, it is proved that every operator in the commutant of T is not unicellular. In particular, T has nontrivial hyperinvariant subspaces. The proof is based on a modification of the reasoning of S.
Maria F. Gamal' (Fri,) studied this question.
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