Let G be a finite group, p a prime, and suppose that every maximal subgroup of G is p-nilpotent or has prime index in G. We prove, relying in the Classification of Finite Simple Groups, that if p is odd and p≠ 5, then G is p-solvable, and the p-length of G is at most $2$. For $p=5$, however, a group G satisfying the same conditions need not be $5$-solvable, and in that case we show that G/S₅(G) PSL₂(11), where S₅(G) is the $5$-solvable radical of G. For $p=2$, groups satisfying our conditions need not be solvable either. We prove, among other properties, that a unique simple group of Lie type, which belongs to the family PSL₂(r2ᵃ) for certain values of the prime r, can be involved in the structure of such groups.
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Beltrán et al. (2024) studied this question.
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