Key points are not available for this paper at this time.
Let G be a Lie group. A unitary representation of G on a Hubert space, 77, is called multiplicty-free if every irreducible representation of G occurs in H with multiplicity zero or one. It is easy to see that this is the case if and only if the ring of bounded G-invariant operators on H is commutative. In this paper we will examine the symplectic analogue of this situation: Let X be a symplectic manifold on which G acts in a Hamiltonian fashion. If one thinks of the bounded operators on H as "quantum observables" and the functions on X as "classical observables" the analogue of the situation above is that the ring of G-invariant functions on X be commutative with respect to Poisson-bracket. If this happens we will say that X is multiplicity-free. We were led to the study of such manifolds by some questions in dynamical systems. Let : X - g* be the moment mapping. A function of the type / , for /: g* - R, is called collective (cf. 6); a completely integrable system consisting of functions of this type is called a collective completely integrable system (see We noticed We also proved that for certain groups, in particular for U(n) and O(n\ this condition is sufficient as well.
Guillemin et al. (Sun,) studied this question.