Withdrawal of cardioprotective therapy in patients with improved cancer therapeutics-related cardiac dysfunction was associated with worse clinical outcomes (P=0.002).
Cohort
No
Does the withdrawal of cardioprotective therapy worsen clinical outcomes in patients with improved cancer therapeutics-related cardiac dysfunction?
Withdrawal of cardioprotective therapy in patients with recovered cancer therapeutics-related cardiac dysfunction is associated with worse clinical outcomes and LVEF decline, especially in those with baseline LVEF <45%.
p-value: p== 0.002
Background: The long-term prognosis after the discontinuation of cardioprotective therapy (CPT) in patients with cancer therapeutics-related cardiac dysfunction (CTRCD) that has shown improvement remains unclear. Objectives: This study aims to assess the prognosis after CPT withdrawal in patients exhibiting improved CTRCD. Methods: In this retrospective analysis of a single-center prospective cohort study, patients with improved CTRCD, defined as an increase in left ventricular ejection fraction (LVEF) ≥10 percentage points from the time of CTRCD diagnosis, were included. We analyzed their clinical outcomes, which included hospitalization for heart failure or a decrease in LVEF ≥10 percentage points within 2 years after CTRCD improvement, alongside echocardiographic changes. Results: = 0.002). Conclusions: Patients who withdrew CPT after demonstrating improvement in CTRCD experienced worse clinical outcomes. Notably, a significant decrease in LVEF was observed after CPT withdrawal in patients with a baseline LVEF <45%.
Park et al. (Tue,) conducted a cohort in Cancer therapeutics-related cardiac dysfunction (CTRCD). Withdrawal of cardioprotective therapy (CPT) was evaluated on Hospitalization for heart failure or a decrease in LVEF ≥10 percentage points within 2 years after CTRCD improvement (p== 0.002). Withdrawal of cardioprotective therapy in patients with improved cancer therapeutics-related cardiac dysfunction was associated with worse clinical outcomes (P=0.002).