Answers are grounded in this paper and cite their sources.
Methane strongly adsorbs on the (110) surface of IrO 2, a rutile-type metal dioxide. Its C–H bond is facilely dissociated even below room temperature, as predicted in a few theoretical works and actually observed in a recent experimental study. Thence, three questions are posed and answered in this paper: First, why does methane adsorb on the IrO 2 surface so strongly? Second, why is the surface so active for the C–H bond breaking reaction? Third, is there any other rutile-type metal dioxide that is more active than IrO 2? A second-order perturbation theoretic approach is successfully applied to the analysis of the electronic structure of methane, which is found to be significantly distorted on the surface. Regarding the first point, it is clarified that an attractive orbital interaction between the surface Ir 5d z 2 orbital and the distorted methane’s highest occupied molecular orbital leads to the strong adsorption. As for the second point, the bond strength between the surface metal atom and the CH 3 fragment generated after the C–H bond scission of methane is correlated well with the activation barrier. A substantial bonding interaction between CH 3 ’s nonbonding orbital and the d z 2 orbital hints at the strong Ir–CH 3 bond and hence high catalytic activity ensues. Last but not least, β-PtO 2, a distorted rutile-type dioxide, is identified as a more active catalyst than IrO 2 . Here again, a perturbation theoretic line of explanation is found to be of tremendous help. This paper is at the intersection of theoretical, catalytic, inorganic, and physical chemistry. Also, it should serve as a model for the design and study of metal-oxide catalysts for the C–H bond activation of methane.
No takes yet. Share an insight, caveat, or question.
Tsuji et al. (2018) studied this question.
Synapse has enriched 10 related papers. Consider them for comparative context: