The reaction between [Me 2 AlCl] and 1 equiv of HN(SiMe 2 H) 2 in CH 2 Cl 2 afforded colorless crystals of [Cl(Me)Al{-NH(SiMe 2 H)}] 2 ( 1 ). The structure of compound 1 has been determined and shows that the bridging NH(SiMe 2 H) groups adopt a mutually trans arrangement. The related reaction between [Me 2 AlCl] and 1 equiv of HN(SiMe 2 Ph) 2 in CH 2 Cl 2 solution resulted in the isolation of colorless crystals. An X-ray crystallographic study showed that the crystals consist of a mixture of [Cl(Me) 2 Al{NH(SiMe 2 Ph) 2 }] ( 2 ) and [Cl 2 (Me)Al{NH(SiMe 2 Ph) 2 }] ( 3 ) in a 1:4 ratio. The formation of compound 3 involves the exchange of one of the methyl groups attached to the aluminum atom with a chlorine atom.
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Carmalt et al. (2003) studied this question.
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