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In this paper we prove that every arithmetical ring satisfies the radical formula.1. Introduction.Throughout this article, rings are assumed to be commutative with unity and modules are assumed to be unitary.Let R be a ring and M an R-module.A proper submodule N of M is said to be a prime submodule of M if ax ∈ N for a ∈ R and x ∈ M implies that either aM ⊆ N or x ∈ N .In this case, P = (N : M ) is a prime ideal of R and N is said to be a P -prime submodule of M .Let N be a proper submodule of M .The intersection of all prime submodules of M containing N is denoted by rad (N ).If no prime submodule of M exists containing N , then rad (N ) is defined to be M .Also, for any subset N of M , the envelope of N , E(N ) is defined to be:ay, a n y ∈ N, for some a ∈ R, y ∈ M and n ∈ N}.In general E(N ) is not a submodule of M .It is clear that E(N ) , the submodule generated by E(N ), is contained in rad (N ).M is said to satisfy the radical formula (M s.t.r.f.), if for every submodule N of M , E(N ) = rad (N ).Furthermore, if every R-module satisfies the radical formula, then R is said to satisfy the radical formula.A ring R is said to be an arithmetical ring if, for all ideals I, J and K of R, we have I + (J ∩ K) = (I + J) ∩ (I + K).Obviously Prüfer domains and, in particular, Dedekind domains are arithmetical.The question of what type of rings s.t.r.f. was considered in [1, 4, 6 9].In [1], it was shown that every arithmetical ring with dim (R) ≤ 1
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Anand Parkash (2012) studied this question.
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