SmCl3 reacts with K2C8H8 to yield the complex Sm(C8H8)Cl·2thf, which reacts with K(2,4-C7H11)(2,4-C7H11= 2,4-dimethylcyclopentadienyl) to form Sm(C8H8)(2,4-C7H11)·thf; the X-ray crystal structure of Sm(C8H8)(2,4-C7H11)·thf shows that the 2,4-dimethylcyclopentadienyl has a ‘U’ conformation.
No takes yet. Share an insight, caveat, or question.
Jin et al. (1991) studied this question.
Synapse has enriched 4 closely related papers on similar clinical questions. Consider them for comparative context: