It is shown experimentally that the volatility of iridium in oxygen at high temperatures is due to the formation of a volatile oxide. The dependence of the partial pressure of this gaseous oxide on the oxygen pressure (in equilibrium with iridium or IrO2) was determined by a transportation method. From the results the formula of the volatile oxide of iridium appeared to be IrO3. The equilibria: 2 Ir(s)+ 3 O2⇄ 2 IrO3(g)and 2 IrO2(s)+ O2⇄ 2 IrO3(g) were measured as a function of the temperature. The results can be expressed as: log Kp(mm) = ‐ 2034/T ‐ 7.346 and log Kp(mm) = ‐ 27596/T + 16.902, respectively.
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Cordfunke et al. (1962) studied this question.
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