Let N ≥ 2, s∈ (0,1), and p ∈ (1, ∞) with $N>sp$. For the fractional p-Laplacian, the power function |x|-γ with 0<γ<N/p-1 satisfies (-Δₚ)ˢ (|x|-γ)=Φ(γ)|x|-γ(p-1)-sp \, in RN\0\. Starting from the power function formula of Del Pezzo and Quaas (2026), we derive a paired integral representation of $Φ$, and show that $Φ$ is strictly increasing and then strictly decreasing, with a unique maximum at N-sp/p. This maximum μ:=Φ(N-sp/p) equals one half of the sharp fractional Hardy constant. Consequently, for every 0<μ<μ, the equation $Φ(γ)=μ$ has exactly two roots 0<γ₋(μ)<N-sp/p<γ₊(μ)<N-sp/p-1. These roots determine the homogeneous solutions |x|^-γ₋(μ) and |x|^-γ₊(μ) of the Hardy equation {equation*} (-Δ_p)^s u - μ{uᵖ⁻¹}{|x|ˢᵖ}=0 in R^N\{0\}, \; u> 0 in R^N \{0\}. {equation*} For 0<μ<μ, we then study the following critical Hardy-Sobolev equation {align}{P}{P} (-Δ_p)^s u-μ{uᵖ⁻¹}{|x|ˢᵖ} = uNp/N-sp-1 in R^N, \; u > 0 in R^N. {align} Let p ≥ 2 and U be a positive, radially symmetric, nonincreasing finite-energy weak solution to {P}. We prove that there exists $C>0$ for which {align*} U(x) ≤ C|x|-γ_-(μ)\;as |x| → 0, and U(x)≤ C|x|-γ_+(μ) \; as |x| → ∞. {align*} Further, we show that γ₋(μ) and γ₊(μ) are the optimal exponents describing the singularity at the origin and the decay at infinity respectively.
No takes yet. Share an insight, caveat, or question.
Biswas et al. (2026) studied this question.
Synapse has enriched 5 closely related papers on similar clinical questions. Consider them for comparative context: