The power word problem for a group G G asks whether an expression u₁x₁ ⋯ uₙxₙ u 1 x 1 ⋯ u n x n , where the uᵢ u i are words over a finite set of generators of G G and the xᵢ x i binary encoded integers, is equal to the identity of G G . It is a restriction of the compressed word problem, where the input word is represented by a straight-line program (i.e., an algebraic circuit over G G ). We start by showing some easy results concerning the power word problem. In particular, the power word problem for a group G G is uNC¹ uNC 1 -many-one reducible to the power word problem for a finite-index subgroup of G G . For our main result, we consider graph products of groups that do not have elements of order two. We show that the power word problem in a fixed such graph product is AC ⁰ AC 0 -Turing-reducible to the word problem for the free group F₂ F 2 and the power word problems of the base groups. Furthermore, we look into the uniform power word problem in a graph product, where the dependence graph and the base groups are part of the input. Given a class of finitely generated groups C C without order two elements, the uniform power word problem in a graph product can be solved in AC ⁰[C₌L ^\,UPowWP\,(C)] AC 0 [ C = L UPowWP ( C ) ] , where \,UPowWP\,(C) UPowWP ( C ) denotes the uniform power word problem for groups from the class C C . As a consequence of our results, the uniform knapsack problem in right-angled Artin groups is NP NP -complete. The present paper is a combination of the two conference papers (Lohrey and Weiß 2019b, Stober and Weiß 2022a). In Stober and Weiß (2022a) our results on graph products were wrongly stated without the additional assumption that the base groups do not have elements of order two. In the present work we correct this mistake. While we strongly conjecture that the result as stated in Stober and Weiß (2022a) is true, our proof relies on this additional assumption.
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Lohrey et al. (2024) studied this question.