Analysis reveals that a biharmonic function is bounded in unbounded domains, suggesting implications for boundary conditions.
The boundedness of the constructed biharmonic function in an unbounded three-dimensional domain is proved if this function and its normal derivative are bounded on the boundary of this domain.
No takes yet. Share an insight, caveat, or question.
Z. R. Ashurova (2025) studied this question.
Synapse has enriched 5 closely related papers on similar clinical questions. Consider them for comparative context: