This research demonstrates pattern avoidance in words using Fibonacci sequences, highlighting implications for permutation theory.
Two k-ary Fibonacci recurrences are aₖ(n) = aₖ(n-1) + k · aₖ(n-2) and bₖ(n) = k · bₖ(n-1) + bₖ(n-2). We provide a simple proof that aₖ(n) is the number of k-regular words over [n] = \1,2,…,n\ that avoid patterns \121, 123, 132, 213\ when using base cases aₖ(0) = aₖ(1) = 1 for any k ≥ 1. This was previously proven by Kuba and Panholzer in the context of Wilf-equivalence for restricted Stirling permutations, and it creates Simion and Schmidt's classic result on the Fibonacci sequence when $k=1$, and the Jacobsthal sequence when $k=2$. We complement this theorem by proving that bₖ(n) is the number of k-regular words over $[n]$ that avoid \122, 213\ with bₖ(0) = bₖ(1) = 1 for any~k ≥ 2. Finally, we conjecture that |Av²ₙ(121, 123, 132, 213)| = a₁(n)² for n ≥ 0. That is, vincularizing the Stirling pattern in Kuba and Panholzer's Jacobsthal result gives the Fibonacci-squared numbers. 20 pages, submitted to special journal issue for Permutation Patterns 2023 (PP23) in DMTCS
No takes yet. Share an insight, caveat, or question.
Downing et al. (2026) studied this question.
Synapse has enriched 5 closely related papers on similar clinical questions. Consider them for comparative context: