Key points are not available for this paper at this time.
Fluoride ions play three roles in the Suzuki–Miyaura reaction. They favor the reaction by formation of trans-ArPdF(PPh3)2, which reacts with Ar′B(OH)2 in an unprecedented rate-determining transmetalation, and by promoting the reductive elimination from the trans-ArPdAr′(PPh3)2 intermediate. Conversely, F− disfavors the reaction by formation of unreactive anionic Ar′B(OH)n−3Fn− (n=1–3), leading to two antagonistic effects of F− in the transmetalation.
Amatore et al. (Fri,) studied this question.