Answers are grounded in this paper and cite their sources.
Dibenzylideneacetone-palladium(0) and -platinum(0) complexes react with dimethylacetylene dicarboxylate to give palladia- and platinia-cyclopentadiene complexes, which are intermediates in the formation of hexamethyl mellitate.
No takes yet. Share an insight, caveat, or question.
Moseley et al. (1971) studied this question.