The mechanism of particle growth of the blue emitting BaMgAl 10 O 17 : Eu 2 + phosphor by firing with AlF 3 has been clarified. It was found that the reaction between BaMgAl 10 O 17 : Eu 2 + and AlF 3 during firing, on the basis of the following chemical equation, results in recreation of BaMgAl 10 O 17 : Eu 2 + with particle growth BaMgAl 10 O 17 : Eu 2 + + ( 4 / 3 ) AlF 3 ⇆ BaMgF 4 : Eu 2 + + ( 17 / 3 ) Al 2 O 3 the firing of BaMgAl 10 O 17 : Eu 2 + with AlF 3 first converts the phosphor into a mixture of the two compounds, BaMgF 4 : Eu 2 + and Al 2 O 3 , at around 1200°C. The BaMgF 4 : Eu 2 + melts at temperatures over 1000°C, then reacts with Al 2 O 3 , and participates in the recreation of both BaMgAl 10 O 17 : Eu 2 + and AlF 3 through a chemical reaction between the two compounds at 1200°C in BaMgF 4 : Eu 2 + solutions. Recreated AlF 3 appears to sublime immediately because it is a material which sublimates with heating. This paper proposes a mechanism for the growth of particle of recreated BaMgAl 10 O 17 : Eu 2 + by the melting of BaMgF 4 : Eu 2 + .
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Oshio et al. (1998) studied this question.