Answers are grounded in this paper and cite their sources.
Reaction of Ru(OAc) 2 (MeO-Biphep) (MeO-Biphep = 6,6‘-dimethoxybiphenyl-2,2‘-diylbis(diarylphosphine)) with 2 equiv of HBF 4 in CH 2 Cl 2 cleaves the MeO-Biphep. Products contain the exotic chelate ligand (aryl) 2 POB(OH)F 2 (aryl = phenyl, p -tolyl, 3,5-di- tert -butylphenyl) together with an (aryl) 2 P−η 6 -arene, 8e donor chelate. The reaction involves a fluorophosphine intermediate.
No takes yet. Share an insight, caveat, or question.
Reijer et al. (1998) studied this question.
Synapse has enriched 10 related papers. Consider them for comparative context: