Given k blue cities, k red cities and a 2k×2k distance matrix, the task in the bipartite travelling salesman problem is to find a shortest tour which alternately visits blue and red cities. We consider the special case of Van der Veen distance matrices and show that it remains NP-hard in general but can be solved in O(k2) time when all vertices with odd indices are blue and all with even indices are red.
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Deı̌neko et al. (2024) studied this question.
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