Minimally invasive mitral valve replacement: Port-access technique, feasibility, and myocardial functional preservation
Key result
Minimally invasive port-access mitral valve replacement in dogs yields excellent recovery of LV function.
- P=0.51
- n=6
Why the study?
Does minimally invasive port-access mitral valve replacement preserve myocardial function in a canine model?
Population
6 mongrel dogs
Comparison
Minimally invasive port-access mitral valve… vs Prebypass baseline values
Design
Preclinical
Follow-up
60 minutes after bypass
Authors
Discussion
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Member takes
Implication
Supports myocardial preservation in canine port-access MVR; leaves open translation to human clinical practice.
Structured PICO
Does minimally invasive port-access mitral valve replacement preserve myocardial function in a canine model?
P
Population
Six mongrel dogs undergoing minimally invasive port-access mitral valve replacement with a St. Jude Medical prosthesis.
I
Intervention
Minimally invasive port-access mitral valve replacement via a 2.5 cm incision with a St. Jude Medical prosthesis, using femoro-femoral cardiopulmonary bypass and a balloon catheter system for myocardial protection with cardioplegic arrest
C
Comparator
Prebypass baseline values
O
Outcome
Valvular performance and myocardial functional recovery (elastance and preload recruitable stroke work) at 30 and 60 minutes after bypasssurrogate
Main Result
p-value: p=0.51
Minimally invasive port-access mitral valve replacement is technically feasible and preserves myocardial function in a canine model, supporting the initiation of clinical trials.
Cite This Study
Schwartz et al. (1997) studied Mitral valve replacement (experimental model) (n=6). Minimally invasive port-access mitral valve replacement vs. Prebypass baseline was evaluated on Recovery of left ventricular function (elastance) (p=0.51). Minimally invasive port-access mitral valve replacement in dogs resulted in excellent recovery of left ventricular function at 60 minutes compared to prebypass baseline (elastance p=0.51).